Answer:
53q+10
Step-by-step explanation:
(-3q+3)+7(8q+1)
-3q+3+56q+7
53q+3+7
53q+10
Given:
A line passes through (-5,-3) and perpendicular to
.
To find:
The equation of the line.
Solution:
We have,

On comparing this equation with slope intercept form, i.e.,
, we get

It means, slope of this line is
.
Product of slopes of two perpendicular lines is always -1.



Slope of required line is
and it passes through the point (-5,-3). So, the equation of the line is

where, m is slope.






Therefore, the equation of required line is
.
The given equations are:
5x - 2y = 88
3x + 4y = 58
Multiplying the 1st equation by 2, we get the new set of equations as:
10x - 4y = 176
3x + 4y = 58
Adding the two equations, we get:
10x - 4y + 3x + 4y = 176 + 58
13x =234
x = 18
Using the value of x in 1st equation, we get:
5(18) - 2y = 88
- 2y = 88 -5(18)
-2y = -2
y = 1
So, the solution of the equation is (18, 1)