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BartSMP [9]
4 years ago
13

How much of the backyard is NOT being used for a vegetable garden or pet exercise area?

Mathematics
1 answer:
Nimfa-mama [501]4 years ago
3 0

Area of backyard is not being used 7792 square feet.

Solution:

Length of the backyard = 181 ft

Width of the backyard = 48 ft

Area of the backyard = length × width

                                   = 181 × 48

Area of the backyard = 8688 square feet

Base of the triangle = 16 ft

Height of the triangle = 28 ft

Area of the triangle = \frac{1}{2}\times \text{base}\times \text{height}

                                 $=\frac{1}{2}\times {16}\times {28}

Area of the triangle = 224 square feet

Length of the rectangle = 32 ft

Width of the rectangle = 21 ft

Area of the rectangular vegetable garden = length × width

                                                                      = 32 × 21

Area of the rectangular vegetable garden = 672 square feet

Area of backyard not used

       = Area of backyard – Area of the triangle + Area of the rectangle

       = 8688 – 224 – 672

       = 7792 square feet

Area of backyard is not being used 7792 square feet.

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Suppose a movie starts at 5:00 p.m. and Lindsay, a customer who is always late, arrives at the movie theater at a random time be
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Answer:

a) We know that the distribution for X is given by: X \sim Unif (a=10, b=45)

The density function for this distirbution is given by:

f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45

So then the height of the uniform density curve would be given by:

h = \frac{1}{35}= 0.029

b) For this case we want to calculate the following probability:

P(X\leq 20)

And we can use the cumulative distribution function given by:

F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45

And we can calculate the probability like this:

P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286

Step-by-step explanation:

For this case we define our random variable X="Lindsay's late arrival time, in minutes"

Part a

We know that the distribution for X is given by: X \sim Unif (a=10, b=45)

The density function for this distirbution is given by:

f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45

So then the height of the uniform density curve would be given by:

h = \frac{1}{35}= 0.029

Part b

For this case we want to calculate the following probability:

P(X\leq 20)

And we can use the cumulative distribution function given by:

F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45

And we can calculate the probability like this:

P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286

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Answer:

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Step-by-step explanation:

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