Yesssssssss, with what though
Answer:
m<N = 76°
Step-by-step explanation:
Given:
∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).
m<J = 64° (given)
Required:
m<N
SOLUTION:
m<K = m<J (base angles of an isosceles ∆ are equal)
m<K = 64° (Substitution)
m<K + m<J + m<JLK = 180° (sum of ∆)
64° + 64° + m<JLK = 180° (substitution)
128° + m<JLK = 180°
subtract 128 from each side
m<JLK = 180° - 128°
m<JLK = 52°
In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.
Thus:
m<MLN = m<JKL (vertical angles are congruent)
m<MLN = 52°
m<M = m<MLN (base angles of isosceles ∆MNL)
m<M = 52° (substitution)
m<N + m<M° + m<MLN = 180° (Sum of ∆)
m<N + 52° + 52° = 180° (Substitution)
m<N + 104° = 180°
subtract 104 from each side
m<N = 180° - 104°
m<N = 76°
Answer:
I know the answer
Step-by-step explanation:
x = random number then y = x + y then x = 68 So we can conclude
Answer:
Answer:
y = -5(x - 7)^3 - 1
Step-by-step explanation:
You kind of just plug in the numbers.
a vertical stretch by a factor of 5: y = 5x^3
a reflection across the x-axis: y = -5x^3
a vertical translation 1 unit down: -5x^3 - 1
a horizontal translation 7 units right: -5(x - 7)^3 -1
Step-by-step explanation:
