6+2x=5-7x WHAT DOES X EQUAL PLEASE ANSWER FAST

Mathematics

2 answers:

ycow [4]3 years ago

7 0

Answer:

x= -1/9

Step-by-step explanation:

6+2x=5-7x

-2x. -2x

6=5-9x

-5. -5

1=-9x/-9

-1/9=x

garri49 [273]3 years ago

4 0

Answer:

x = -0.111111111 *repeating decimal

Step-by-step explanation:

6 + 2x = 5 - 7x (Add 7x)

6 + 9x = 5 (Subtract 6)

9x = -1 (Divide by 9)

x = -0.11111111 ...

6 + 2(-0.111) = 5 - 7(-0.111)

6 + -0.222 = 5 - (-0.777)

5.777 = 5.777

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Ilia_Sergeevich [38]

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3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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4 years ago

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Hunter-Best [27]

The answer is B (Sorry for the bad handwriting.)