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TEA [102]
3 years ago
7

8. What is the sum of the exterior angles of

Mathematics
2 answers:
PolarNik [594]3 years ago
6 0

Answer:

D. 1080°

Step-by-step explanation:

Sum=(n-2)x180°

(8-2)x180°

6x180°

1080°

Hope it helps ❤

andrezito [222]3 years ago
6 0

Answer: 360°

Step-by-step explanation:

The sum of the exterior angle of a polygon is always 360°

Or, From the sum of the interior angle of a polygon,

(2n - 4)× 90° where n = 8

(2 × 8 - 4) × 90 =

16 - 4 × 90

12 × 90 = 1080°

Now each interior angles of the polygon

= 1080/8

= 135°.

Now, to find each exterior angle of the polygon,

= 180°- 135°

= 45°

To find the exterior angle now, we multiply 45° by eight

= 45° × 8

= 360°

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Answer:

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Step-by-step explanation:

Given:

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Substituting values given for length and width.

Perimeter of sand box = 2(5\frac{1}{3}+3\frac{3}{4})\ feet

Simplifying by adding fractions:

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⇒  2(8+\frac{1}{3}+\frac{3}{4}) feet

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To add fractions we take LCD for the denominators 3,4,1.

LCD for 3 and 4 = 12 as its the least common multiple of 3,4,1.

Making denominators =12 by multiplying numerator an denominator with the corresponding numbers

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⇒  2(\frac{96}{12}+\frac{4}{12}+\frac{9}{12}) feet

Then we simply add numerators.

⇒  2(\frac{96+4+9}{12}) feet

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Reason:

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