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Tom [10]
3 years ago
8

Can you guys help me out with this question?

Mathematics
2 answers:
kirill [66]3 years ago
7 0

Answer:

12

Step-by-step explanation:

12-8=8

d1i1m1o1n [39]3 years ago
7 0
The answer is 12 hope this helped:)
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The area of a rectangle is 70 m², and the length of the rectangle is 11 m less than three times the width. Find the dimensions o
11111nata11111 [884]

Step-by-step explanation:

the area of a rectangle is

length × width

in our case

length × width = 70 m²

length = 3×width - 11

we can use this second equation in the first and get

(3×width - 11) × width = 70

3×width² - 11×width - 70 = 0

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 3

b = -11

c = -70

x = (11 ± sqrt((-11)² - 4×3×-70))/(2×3) =

= (11 ± sqrt(121 + 840))/6 =

= (11 ± sqrt(961))/6

x1 = (11 + 31)/6 = 42/6 = 7

x2 = (11 - 31)/6 = -20/6 = -10/3

the negative solution is not applicable for a length in an object.

so, only x1 = 7 m is our solution.

the width of the rectangle is 7 m.

the length = 3×width - 11 = 3×7 - 11 = 21-11 = 10 m

7 0
2 years ago
What is the equivalent to 13/75?
Rama09 [41]
13 is prime, so 13/75 can't be reduced.  You could, however, 
write

13/75 = 0.17333...    This is a repeating decimal.
7 0
3 years ago
Using the given statements, state whether the conditional statement is true or false.
SIZIF [17.4K]

the statement is true because 4 and 7 are different

5 0
3 years ago
What is the perimeter of triangle ABC?
julia-pushkina [17]

Answer:

18 units

Step-by-step explanation:

Using the midpoint theorem, the perimeter of the triangle formed by joining the midpoints of the original triangle is exactly half the size in perimeter

What we mean in this case is that the perimeter of BAC IS two times the perimeter of EDF

perimeter of EDF is the sum of all the sides = 2 + 4 + 3 = 9

So the perimeter of BAC is 2 * 9 = 18

8 0
3 years ago
A right triangle has side lengths 9, 40, and 41 as shown below.
Mashutka [201]

Answer:

cos B = 9/41

tan B = 40/9

sin B = 40/41

Step-by-step explanation:

There is no picture, so I am making a few assumptions.

I am assuming that angle C is the right angle and is opposite 41.

I am also assuming that angle B is formed by the sides that measure 9 and 41. The hypotenuse is 41.

For angle B, the adjacent leg is 9, and the opposite leg is 40.

cos B = adj/hyp = 9/41

tan B = opp/adj = 40/9

sin B = opp/hyp = 40/41

5 0
3 years ago
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