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oee [108]
3 years ago
5

A child puts one five-rupee coin of her saving in the piggy bank on the first day. She increases her saving by one five-rupee co

in daily. If the piggy bank can hold 190 coins of five rupees in all, find the number of days she can continue to put the five-rupee coins into it and find the total money she saved.
Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

1 day => 1 coin

190 days => 190 coins (full)

so it takes 190-1=189 more days to fill it

total money saved = 190x5=950 rupees

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Answer: 1¹/₈ hours

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I need help with this one asap please and thank you
inna [77]

Answer:

C

Step-by-step explanation:

A

(m² - 3m + 2) / (m² - m)

we see due to a little bit of experience with expressions and multiplications of expressions that

(m² - 3m + 2) = (m - 2)(m - 1)

(m² - m) = m(m - 1)

so,

(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m

so, that's not it.

B

(m² - 2m + 1) / (m - 1)

we see again

(m² - 2m + 1) = (m - 1)(m - 1)

so,

(m - 1)(m - 1) / (m - 1) = m - 1

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C

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(m² - m - 2) = (m - 2)(m + 1)

and

(m² - 1) = (m + 1)(m - 1)

so,

(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)

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D

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no, that is not a solution.

8 0
2 years ago
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