The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
<h3>Determining the perimeter and area of the triangle giving line equation</h3>
In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.
The points of intersection of the line are;
(x₁, y₁) = (- 0.4, 5.2),
(x₂, y₂) = (-0.8, 4.4),
(x₃, y₃) = (0, 4)
Determine the base
b² = c² -a²
b = √(-0.8)² + (4 - 4.4)²
b = 2√5 / 5
Determine the height
h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²
height = 2√5 / 5
For the hypotenuse
r = √2 · b
r = 2√10 / 5
<h3>Determine the Perimeter and area</h3>
Perimeter = s1+s2+s3
Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5
Perimeter = (2√10 + 4√5) / 5 units
<u>For the area</u>
area = 1/2* base * height
A = 0.5 · (2√5 / 5) · (2√5 / 5)
A = 2/5 square units
Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
Learn more on area and perimeter of triangles here: brainly.com/question/12010318
#SPJ1
Answer:
add
Step-by-step explanation:
Step-by-step explanation:
hope it helps
brainliest please
A.P. series would be: 201, 204, 207 .... 597
Here, a = 201, d = 3, l = 597
Now, l = a + (n - 1) d
597 = 201 + (n - 1)3
597 - 201 = 3n - 3
396 + 3 = 3n
n = 399/3
n = 133
In short, Your Answer would be 133
Hope this helps!