$\dfrac{2+6i}{2-4i}\\\\\\=\dfrac{2(1+3i)}{2(1-2i)}\\\\\\=\dfrac{1+3i}{1-2i}\\\\\\=\dfrac{(1+3i)(1+2i)}{(1-2i)(1+2i)}\\\\\\=\dfrac{1+2i+3i+6i^2}{1-(2i)^2}\\\\\\=\dfrac{1+5i-6}{1+4}~~~~;[i^2=-1]\\\\\\=\dfrac{5i-5}{5}\\\\\\=\dfrac{5(i-1)}5\\\\=i-1\\\\=-1+i\\\\\text{It is in a form of a +bi so,}~ a = -1~ \text{and}~ b = 1$

6 0

3 years ago

TIMER !! HELP!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

The vertex of a parabola lies on the axis of symmetry.

8 0

2 years ago

How do you know when an expression is its simplest form

marishachu [46]

Answer:

you know it is when you can't solve it any further. If the numbers cannot be divided by a common number. there is no possible way to make it any more compacted.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If anyone knows please help me

pishuonlain [190]

Answer:

Step-by-step explanation:

Standard form of a circle is given by,

(x - a)² + (y - b)² = r²

Here, (a, b) is the center and 'r' is the radius of the circle.

For a circle having center (8, -4) and radius r = 1

Equation of the circle will be,

(x - 8)² + (y + 4)² = 1²

(x - 8)² + (y + 4)² = 1

Option (1) is the answer.

Question (2)

Circle with the center (-1, 0) and a point (2, -4) on it,

Radius of the circle = Distance between the center and the given point on circumference

= $\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

= $\sqrt{(-1-2)^2+(0+4)^2}$

= $\sqrt{9+16}$

= 5

Therefore, equation of the circle will be,

(x + 1)² + (y - 0)² = 5²

(x + 1)² + y² = 25

8 0

3 years ago