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brilliants [131]
3 years ago
8

22 gallons of gas cost $65.56. What is the unit rate for 1 gallon of gas?

Mathematics
2 answers:
alekssr [168]3 years ago
6 0
<span>divide 65.56/22= 2.98 per gallon. </span>
Ronch [10]3 years ago
6 0

Answer:

2.98

Step-by-step explanation:

i have done this already and can comfirm it is correct

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No links, will give brainliest
nadezda [96]

The area of a parallelogram is base x height, or A = bh.

a) A = 6 x 10, so A = 60 cm²

b) A = 15 x 8, so A = 120 cm²

6 0
3 years ago
Question 3: Marla bought one necklace and two bracelets for $67.50. Use the following information to determine the amount she pa
Butoxors [25]

Answer:

Each bracelet costs 20.25

Step-by-step explanation:

Here's what was given in the equation:

Total Price: $67.50

Price of necklace: $27

We can subtract the $27 from the $67.50 to get $40.5

Since we know that both bracelets are the same price we can divide the $40.5 by 2 to get two of the exact same prices. The result is $20.25 for each bracelet.

<em>Hope this helps</em>

5 0
3 years ago
Eli is driving on a long road trip. He currently has 12 gallons of gas in his car. Each
AlladinOne [14]

Answer:

I would be 7 gallons used and 5 gallons left

Step-by-step explanation:

multyply 1.75 times 4 hours equal 7 then 12-7=5 is the total of gallons left

Hope this helps

5 0
3 years ago
Read 2 more answers
(9+4c)+(2+3x) add timed so hurry!
Luba_88 [7]

Answer: 3x + 4c + 11

Step-by-step explanation: Combine like terms.

5 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}

6 0
3 years ago
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