The equation that is in point-slope form for a line that goes through (2,-6) and has a slope of -3/4 is y+6=-3/4(x-2).
The equation for point-slope is y-y1=m(x-x1). So just take the given info and plug it in. Since the y-point is negative, it becomes a positive in the equation.
Reflection over the y-axis, translation 2 units down
Answer:
y =mx+b
Step-by-step explanation:
this is what I have learned
Answer:
-a^2 + -a + 12
Step-by-step explanation:
Expand the following:
(3 - a) (a + 4)
(3 - a) (a + 4) = (3) (a) + (3) (4) + (-a) (a) + (-a) (4):
-a a + 3 a - 4 a + 3 4
3×4 = 12:
-a a + 3 a - 4 a + 12
-a a = -a^2:
-a^2 + 3 a - 4 a + 12
Grouping like terms, -a^2 + 3 a + 4 (-1) a + 12 = -a^2 + (3 a - 4 a) + 12:
-a^2 + (3 a - 4 a) + 12
3 a - 4 a = -a:
Answer: -a^2 + -a + 12
Answer: Parallel lines have the same slope
y = 2x +b
Use the given point (2, 5)
5 = 2(2) +b
b = 5 -4 = 1
The equation of the line is
y = 2x +1
Note general form of the slope-intercept form of a line is y = mx +b, where m is the slope and b is the y-axis intercept
Step-by-step explanation:
