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m_a_m_a [10]
3 years ago
13

The system of equations is graphed on the coordinate plane.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0

The solution is: (-1,-2)

Step-by-step explanation:

Given equations are:

y = x-1\ \ \ Eqn1\\y = -2x-4\ \ \ Eqn2

In order to solve two equations with graphing method, the graphs of two equations are made which are straight lines the point of intersection is the solution of the equations.

Here,

The graph is given

To read the solution of the graph we see that on which x and y- coordinates the point of intersection is. then the answer is written as (x-coordinate , y-coordinate)

The solution point is highlighted with a circle. The x-coordinate is -1 and y-coordinate is -2

So,

The solution is: (-1,-2)

Keywords: Linear Equations, Graphing

Learn more about linear equations at:

  • brainly.com/question/6105786
  • brainly.com/question/6075514

#LearnwithBrainly

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Answer:

The first one

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To figure out which one is the best deal, for each one how much <em>one</em> t-shirt costs.

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To figure out how much money one t-shirt would cost, you divide $28.95 by 3.

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<u>Second deal:</u>

4 t-shirts for $39

Same thing as the last one, except since there are 4 t-shirts you divide $39 by 4.

1 t-shirt = 39/4 = $9.75

<u>Third deal:</u>

5 t-shirts for $49.95

This time you will divide 49.95 by 5.

1 t-shirt = 49.95/5 = $9.99

The last step is to compare the three deals, and since you are trying to find the one that costs the <em>least</em> you can see that the first deal is the best one, because $9.65 per shirt is cheaper than $9.75 and $9.99

5 0
3 years ago
Jimmy's school is selling tickets to the
natka813 [3]
Children’s tickets are $4, adult tickets are $14




Explanation:

4a+6c=80

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Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)
DiKsa [7]

Answer:

The standard equation of the sphere is (x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Let the first endpoint be represented as (x_{1}, y_{1}, z_{1}) and the second endpoint be (x_{2}, y_{2}, z_{2}).

Hence,

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Midpoint = (\frac{3 + 7  }{2}, \frac{-2+12 }{2}, \frac{4 + 4  }{2})

Midpoint = (\frac{10 }{2}, \frac{10}{2}, \frac{8  }{2})\\

Midpoint = (5, 5, 4)

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2}      }

d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}

d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}

d = \sqrt{16 +196 + 0

d =\sqrt{212}

d = 2\sqrt{53}

This is the diameter

To find the radius, r

From Radius = \frac{Diameter}{2}

Radius = \frac{2\sqrt{53} }{2}

∴ Radius = \sqrt{53}

r = \sqrt{53}

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is (5, 5, 4)

Radius of the sphere is \sqrt{53}

The equation of a sphere of radius r and center (h,k,l) is given by

(x-h)^{2} + (y-k)^{2} + (z-l)^{2}  = r^{2}

Hence, the equation of the sphere of radius \sqrt{53} and center (5, 5, 4) is

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = \sqrt{(53} )^{2}

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

This is the standard equation of the sphere

6 0
3 years ago
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