Please help need help to pass my class plz

Humans developed antibiotics to fight bacterial infections. However, some antibiotics are no longer effective in killing the bac

emmasim [6.3K]

Genetic variation in bacterial made it possible for some individuals to have resistance to the antibiotic, survive, and reproduce is a statement that explains the theory of evolution very well. Some of the bacteria that became resistant to the antibiotics, passes this down the genes for drug resistance. I hope the answer helps you.

8 0

3 years ago

Read 2 more answers

Which statement is mostly likely to apply to a cell that has DNA within it cytoplasm

klemol [59]

It performs all functions for the organism.

Hope this helps!

4 0

3 years ago

The sequence of an mRNA transcript is UGGCACUCCAG. What will be the sequence of the template DNA strand from which it was synthe

Keith_Richards [23]

The sequence of the template DNA strand of the mRNA transcript of UGGCACUCCAG is ACCGTGAGGTC. This is from the pairing of U to A, G to C, C to G, A to T and T to U. In this case, the abbreviations refer to the nitrogen bases that are the biulding blocks of the DNA strands.

5 0

3 years ago

When immobilizing the patient's head to the long backboard you should?

Kruka [31]

Use a sandbag to hold it in place

8 0

3 years ago

In beans the pod texture and growth form genes are located on different chromosomes. There are two varieties of beans in a farme

irina1246 [14]

Answer:

a. Genotype in F1 - TtBb

Phenotype in F1 - tough pods, bush-type growth

b. Proportion of F2 that are heterozygous for bush-type growth form = 5/8

c. Proportion of the F2 with tender pods = 1/4

d. Proportion of F2 that are heterozygous for growth form and have tender pods = 1/8

Explanation:

Since the two traits are located on different chromosomes, they will independently assort during gametes formation. T is dominant over t and B is dominant over b.

Two true-breeding varieties were crossed at the beginning of the program:

TTBB x ttbb

All F1 plants will have the genotype TtBb with tough pods and bush-type growth form.

Advancing the cross to F2:

TtBb x TtBb

Progeny

1 TTBB - tough pods, bush-type

2 TTBb - tough pods, bush-type

2 TtBB - tough pods, bush-type

4 TtBb - tough pods, bush-type

1 TTbb - tough pods, climbing-type

2 Ttbb - tough pods, climbing-type

1 ttBB - tender pods, bush-type

2 ttBb - tender pods, bush-type

1 ttbb - tender pods, climbing-type

Proportion of F2 that are heterozygous for bush-type growth form = 10/16 = 5/8

Proportion of the F2 with tender pods = 4/16 = 1/4

Proportion of F2 that are heterozygous for growth form and have tender pods = 2/16 = 1/8

7 0

3 years ago