Answer
given,
distance = 140 m
time, t = 3.6 s
moving speed = 53 m/s
a) distance = (average velocity) x time
v₀ + 53 = 77.78
v₀ = 24.78 m/s or 25 m/s
b)
a = 7.8 m/s²
using equation of motion
v₀² = v₁² + 2 a s
53² = 0²+ 2 x 7.8 x s
s = 180 m
The kinetic energy halfway the hill is
Explanation:
If there are no friction forces acting on the cart, we can apply the law of conservation of energy: the mechanical energy of the cart (which is the sum of potential energy + kinetic energy) must be conserved. So we can write:
where
is the initial potential energy, at point A, with
m = 980 kg (mass of the cart)
(acceleration of gravity)
(height at point A)
is the initial kinetic energy, at point A
, with
(velocity at point A)
is the final potential energy, at point B, where
(height at point B)
is the final kinetic energy, at point B, where
is the velocity at point B
Here we are interested in finding , so by re-arranging the equation and substituting we find:
Learn more about kinetic energy:
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