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olchik [2.2K]
3 years ago
13

A cup of hot coffee has been left to cool in a room with an ambient temperature of 21^\circ{\text{C}}21 ∘ C21, degrees, start te

xt, C, end text. The relationship between the elapsed time, mmm, in minutes, since the coffee was left to cool, and the temperature of the coffee, TTT, measured in ^\circ C ∘ Cdegrees, C, is modeled by the following function. T(m)=21+74 \cdot 10^{-0.03m}T(m)=21+74⋅10 −0.03m T, (, m, ), equals, 21, plus, 74, dot, 10, start superscript, minus, 0, point, 03, m, end superscript. What will the temperature of the coffee be after 101010 minutes?

Physics
1 answer:
Kay [80]3 years ago
6 0

Answer:

Explanation:

From the equation given ; T(m)=21+74⋅10 −0.03m

Plugging the value of m = 10minutes for the time to calculate the temperature at that time instant. The detailed steps is as shown in the attached file

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