Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
There isn’t a picture but hopefully I can help u
Answer:
Yes.
Step-by-step explanation:
Set the equations equal to each other to determine their equality.
-4[3(x - 7)] = 6(14 - 2x)
Distribute the 3 and the 6 into their respective parenthesis.
-4[3x - 21] = 84 - 12x
Distribute the -4 into the brackets.
-12x + 84
Rearrange the equations.
84 - 12x = 84 - 12x
Since the equations come out to be the same thing on both sides so that any value satisfies it, the equations are equivalent.
Suppose you can factorize:
Then by expanding the right side, you have
which means in this case, you have to have
The answer is 1 and 4/5. Just divide and put the remainder as the numerator and the numerator stays the same
