a right triangle has legs measuring 4.5 meters and 1.5 meters the lengths of the legs of a second triangle are proportional to t
2 answers:
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Answer:
A quadratic function.
Step-by-step explanation:
If you plot the points given in the table, you obtain the graph shown in the figure attached.
As you can see, it is a parabola, therefore, the function that best models the data is a quadratic function.
By definition, the parent function of a quadratic function is:
You can compress or stretch it in the y-direction by multiplying the function by a constant :
If , then the function is compressed.
If , then the function is stretched.
You can find the constant of the function asked as following:
- Substitute x=1 into the parent function to obtain the y-coordinate:
Then the point is (1,1)
- As you can see, with x=1 you obtain y=1 in the parent function, and in the function given in the table when x=1, y=2.5, therefore, the function is multiplied by 2.5. Therefore the constant is:
Then the function is:
The parameterize is 128
In mathematics, and extra in particular in geometry, parametrization (or parameterization; additionally parameterization, parametrization) is the method of locating parametric equations of a curve, a surface, or, greater typically, a manifold or an expansion, described by using an implicit equation.
"To parameterize" by means of itself method "to specific in terms of parameters". Parametrization is a mathematical technique that includes expressing the state of a system, system, or model as a feature of some independent portions referred to as parameters.
Instance 1. find a parametrization of the road through the points (three,1,2) and (1,0,5). answer: the road is parallel to the vector v=(3,1,2)−(1,0,five)=(2,1,−3). subsequently, a parametrization for the line is x=(1,0,five)+t(2,1,−3)for−∞
volume by both the methods
Directly step
{(n-y) dx+(x+y) by = √(3 co
{{(x-y)dx+(x+y) by =
ts-8 sin(t)) (8 sinct) df
t=o + (8 cost+ 8 sinds) 8 cast, dt]
25
(64 cosit,sin (4) +64 sin'? (+ 64 cs) +64 cost) sint) at
205
-(ou (ents) cost() dt = } 64 dt =64() ?
+
=
64 (211-0)
=1281
using Green's Thoerem. Step (2)
- §pdxxQdy = SS (2(244) - 2. (214) G
Jy
D
dA
=
SSC- (U)dA= [[2dA = 2 [SdA
D
D
=24
=2 182
where (A=112 area of the
= 128
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