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2 years ago

Y varies jointly as x, z, and w. when x=2, z=1, and w=12, then y=72. find y when x=1, z=2, and w=3

1 answer:

7 0

ANSWER: 18

EXPLANATION:

y=kxzw

where k is a constant
Making k the subject of the formula, we have

k=y/xzw

Inputting the values

k= 72/(2)(1)(12)

k=72/24

k = 3

Solving for y when x=1,z=2 and w=3

We have

y=kxzw

y = (3)(1)(2)(3)

y = 18

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Answer:

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Step-by-step explanation:

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2.2360679775

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2 years ago

What is the y intercept

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3 years ago

A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the

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Answer:

Price of widget to break even= $37.9

Step-by-step explanation:

We are told that the equation representing the amount of profit, y, made by the company, in relation to the selling price of each widget, x is;

y = -8x² + 348x - 1705

Now, the company will break even when it has made no profit. That is when, y = 0

Thus;

0 = -8x² + 348x - 1705

Rearranging,

8x² - 348x + 1705 = 0

Using quadratic formula ;

x = [-b ± √(b² - 4ac)]/2a

x = [-8 ± √(-348² - 4•1•1705)]/(2 x 8)

x = $5.63 or $37.87

We'll use $37.87 because it is the highest price for which no profit is made, and higher price means that we could sell least number of products to earn a certain amount of money.

We are told to approximate to nearest cent. Thus,

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3 years ago

Two Social Security numbers (see Exercise 8.12) match zeros if a digit of one number is zero iff the corresponding digit of the

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Answer:

Proved

Step-by-step explanation:

From the given parameters, we have:

$n = 9$ i.e. the length of each security numbers

$r = 2$ i.e. 2 security numbers

Required

In 513 security numbers, 2 must have matching zeros

To do this, we make use of Pigeonhole principle.

First, we calculate the number of all security numbers not having matching zeros.

Each of the 9 digits can be selected in 2 ways.

2 ways implies that each digit is either 0 or not

So, total selection is:

$Total = 2^9$

$Total = 512$

Apply Pigeonhole principle

The principle states that: suppose there are n items in m containers, where $n>m$ , then there is at least one container that contains more than 1 item.

This means that if there are 512 security number without matching zeros, then there is 1 (i.e. 512 + 1) with matching zeros.

$512 + 1 = 513$

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3 years ago

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2 years ago

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