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2 years ago

Y varies jointly as x, z, and w. when x=2, z=1, and w=12, then y=72. find y when x=1, z=2, and w=3

1 answer:

7 0

ANSWER: 18

EXPLANATION:

y=kxzw

where k is a constant
Making k the subject of the formula, we have

k=y/xzw

Inputting the values

k= 72/(2)(1)(12)

k=72/24

k = 3

Solving for y when x=1,z=2 and w=3

We have

y=kxzw

y = (3)(1)(2)(3)

y = 18

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What is the solution of the system?

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Greetings!

Solve the System, using Elimination:
$\left \{ {{4x+2y=18} \atop {2x+3y=15}} \right.$

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$\left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.$

Eliminate variable x:
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Divide both sides by 4:
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Input this value into one of the Equations:
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Simplify:
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$(4x+6)+(-6)=(18)+(-6)$

$4x=12$

Divide both sides by 4.
$\frac{4x}{4}= \frac{12}{4}$

$x=3$

The Solution to this System (The Point of Intersection):
$\boxed{(3,3)}$

I hope this helped!
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