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Kay [80]
3 years ago
7

Suppose you had a balloon containing 1 mole of helium at STP and a balloon containing 1 mole of oxygen at STP. Which statement(s

) is(are) TRUE?
(A) The balloons will have the same volume.
(B) The balloons will have the same mass.
C) (Both A) and B) are true.
(D) Neither A) nor B) are true.
(E) not enough information
Chemistry
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

The true statement  is option A.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas =  1 atm

V = Volume of gas = ?

n = number of moles of gas = 1 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K

V=\frac{nRT}{P}=\frac{1 mol\times 0.0821 atm L/mol K\times 273.15 K}{1 atm}

V = 22.42 L

This means that 1 mole of an ideal gas at STP occupies 22.42 liters of volume.

So, 1 mole of helium gas and 1 mole of oxygen gas will have same value of volume in their respective balloons at STP.

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Which of the following statements is NOT true?
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Answer : The incorrect statements are:

(A) When two nonmetals react, the compound formed is ionic.

(B) Two nonmetals can undergo an oxidation-reduction reaction.

Explanation :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

The two nonmetals can not undergo an oxidation-reduction reaction.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The metal-nonmetal reaction can always be assumed to be an oxidation-reduction reaction.

For example : 2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

In this reaction, sodium shows oxidation because the oxidation state changes from (0) to (+1) and and chlorine shows reduction because the oxidation state changes from (0) to (-1).

Hence, the incorrect statements are, (A) and (B)

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3 years ago
An aqueous solution is 0.467 m in hcl. what is the molality of the solution if the density is 1.23 g/ml?
Reika [66]
Answer:
molarity = 0.385 moles/kg

Explanation:
Assume that the volume of the aqueous solution given is 1 liter = 1000 ml
Now, density can be calculated using the following rule:
density = mass / volume
Therefore:
mass = density * volume = 1.23 * 1000 = 1230 grams
Now, 0.467 m/L * 1L = 0.467 moles of HCl
We will get the mass of the 0.467 moles of HCl as follows:
mass = molar mass * number of moles = (1+35.5)*0.467 = 17.0455 grams
Now, we have the mass of the solution (water + HCl) calculated as 1230 grams and the mass of the HCl calculated as 17.0455 grams. We can use this information to get the mass of water as follows:
mass of water = 1230 - 17.0455 = 1212.9545 grams
Finally, we will get the molarity as follows:
molarity = number of moles of solute / kg of solution
molarity = (0.467) / (1212.9594*10^-3)
molarity = 0.385 mole/kg 

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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