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Kay [80]
3 years ago
7

Suppose you had a balloon containing 1 mole of helium at STP and a balloon containing 1 mole of oxygen at STP. Which statement(s

) is(are) TRUE?
(A) The balloons will have the same volume.
(B) The balloons will have the same mass.
C) (Both A) and B) are true.
(D) Neither A) nor B) are true.
(E) not enough information
Chemistry
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

The true statement  is option A.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas =  1 atm

V = Volume of gas = ?

n = number of moles of gas = 1 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K

V=\frac{nRT}{P}=\frac{1 mol\times 0.0821 atm L/mol K\times 273.15 K}{1 atm}

V = 22.42 L

This means that 1 mole of an ideal gas at STP occupies 22.42 liters of volume.

So, 1 mole of helium gas and 1 mole of oxygen gas will have same value of volume in their respective balloons at STP.

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Lastly, we calculate the amount of P2O5 produced.

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How much atomic mass does Osmium have
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190.23g

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Calculate the heat required to melt 25.7 g of solid methanol at its melting point
umka2103 [35]

The heat required to melt the compound is<u> 2.56kJ.</u>

Why?

To calculate the heat required to melt 25.7 g of solid methanol, we need to calculate its molar mass, know its chemical formula, its molar heat of fusion, and calculate how many moles represent 25.7g of the same compound.

Then, we need to use the following formula to calculate the heat:

Q=N*u

Where,

N is the moles of the compound

u, is the molar heat of fusion of the compound (J/mol)

We know that the molar mass of methanol is :

32.042\frac{g}{mol}

So, we can calculate the number of moles that represents 25.7g of the same compound:

N=\frac{mass(g)}{molarmass(\frac{g}{mol}} \\\\N=\frac{25.7g}{32.042\frac{g}{mol}}=0.8mol(methanol)

Also, the molar heat of fusion of methanol is:

u_{methanol}=3200\frac{J}{mol}=3.2\frac{kJ}{mol}

Now, substituting into the first equation and calculating, we have:

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Have a nice day!

4 0
3 years ago
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The radius of a gold atom is 144 pm. How many gold atoms would have to be laid side by side to span a distance of 4.97 mm
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Answer:

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D/d = 4.97 mm × 10⁻³ m/2.28 × 10⁻¹⁰ m = 2.18 × 10⁷

3 0
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