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Troyanec [42]
3 years ago
8

Choose the ground state electron configuration for Cr3+.

Chemistry
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

b) [Ar]4s²3d1¹

Explanation:

Chromium, Cr, is the atom with atomic number 24 (That is, 24 protons).

A Cr³⁺ contains 3 electrons less than number of protons. That is 21electrons.

The Argon, Ar, contains 18 electrons. That means the electronic configuration of Cr³⁺ contains 3 electrons more than Ar.

Following the Hund's rule, these three electrons will occupy the 4S orbital (2 electrons) and the 2d orbital (1 electron).  

Thus, right solution is:

<h3>b) [Ar]4s²3d1¹</h3>

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5 0
3 years ago
A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.
irga5000 [103]

Answer:

1. pH = 1.23.

2. H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the pKa is:

pKa=-log(Ka)=-log(5.90x10^{-2})=1.23

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Which is also shown in net ionic notation.

Best regards!

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What is the molarity of a solution that contains 200. 0 g of lithium chloride in 450 mL? molar mass of chloride= 42. 394g/mol
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Explanation:

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