Answer:
0.11%
Explanation:
Without mincing words, let us dive straight into the solution to the question/problem. The first step to solve this question is to write out the chemical reaction, that is the reaction showing the dissociation of acetic acid.
CH3COOH <=======================================> CH3COO⁻ + H⁺
Initially, the amount present in the acetic acid which is = 12M, the concentration for CH3COO⁻ and H⁺ is 0 respectively.
At equilibrium, the amount present in the acetic acid which is = 12 - x, the concentration for CH3COO⁻ = x and H⁺ = x respectively. Note that the ka for acetic acid = 1.8 × 10⁻⁵.
1.8 × 10⁻⁵ = x²/ 14 - x. Therefore, x = 0.0158 M.
The next thing to do is to calculate for the percentage of dissociation, this can be done as given below:
percentage of dissociation = x/14 × 100. Recall that the value that we got for x = 0.0158 M. Hence, the percentage of dissociation = 0.0158 M/ 14m × 100 = 0.11%
<span>For the answer to the question above,
Addition of HCl causes a precipitate to form:
Ag+ & Cl- -- AgCl a white ppt
H2SO4 is added to the supernate another precipitate forms:
Ba+2 & SO4-2 --> BaSO4 a white ppt
a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed:
no Mn+2 & no Cu+2 which would have ppt as hydroxides</span>
I hope this helps you.
When Al(OH)3 and H2SO4 are allowed to react, the products formed are aluminum sulfate (Al2(SO4)3<span> ) and water (H2O). The balanced equation should be written as follows:
</span><span>3H2SO4 + 2Al(OH)3 = Al2(SO4)3 + 6H2O
This reaction is called a neutralization reaction. Hope this answers the question. Have a nice day.</span>
Answer:
14 H i think , but i believe that thats the answer
Answer:
dfsgvhyjnkmljkhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
yhgtu
Explanation:olkkjl
