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AnnZ [28]
4 years ago
15

How can cybercrime harm a person whose personal information they have stolen

Computers and Technology
1 answer:
telo118 [61]4 years ago
6 0
There location can easily be found, credit card information could have been found, and the thief could even pose as the victim.
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3 years ago
Which of these is NOT an example of lifelong learning?
oee [108]

Answer:

B. having lunch with a friend

Explanation:

Lifelong learning can be defined as a continuous, self-motivated, and self-initiated learning activity that is typically focused on personal or professional development. Thus, it's a form of education that is undertaken throughout life with the sole aim of pursuing knowledge, competencies, and skills for either personal or professional growth and development, especially after acquiring a formal education.

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7 0
3 years ago
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Triss [41]
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7 0
3 years ago
While microsoft excel can be an efficient tool for developing a dss, compared to using a programming language like c++, a shortc
klasskru [66]
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3 0
4 years ago
Hey, I am in need of urgent help! My teacher is REALLY bad at his job (no exaggeration) and if I dont get a 100 on this lab, I w
anygoal [31]

Answer:

public class CircularList

{

  private ListNode head; // front of the LinkedList

  private ListNode tail; // last node of the LinkedList

  private int size; // size of the LinkedList

   

  // constructs a new CircularList

  public CircularList()

  {

    head = tail = null;

    size = 0;

  }

   

  // returns the size of the array

  public int size()

  {

     return size;

  }

   

  // returns whether the list is empty

  public boolean isEmpty()

  {

     return (size == 0);

  }

   

  // returns the value of the first node

  public Integer first()

  {

     if (head != null) {

       return head.getValue();

     }

     return -1;

  }

   

  // returns the value of the last node

  public Integer last()

  {

     if (tail != null) {

       return tail.getValue();

     }

     return -1;

  }

  // adds a node to the front of the list

  public void addFirst(Integer value)

  {

    head = new ListNode(value, head);

    if (tail == null) {

      tail = head;

    }

    size++;

  }

   

  // adds a node to the end of the list

  public void addLast(Integer value)

  {

    ListNode newTail = new ListNode(value, null);

    if (tail != null) {

      tail.setNext(newTail);

      tail = newTail;

    } else {

      head = tail = newTail;

    }

     

    size++;

  }

   

  // adds a node at the position pos  

  public void addAtPos(int pos, Integer value)

  {

     if (pos == 0) { // Add at the start

       addFirst(value);

       return;

     }

     if (pos <= 0 || pos > size) { // Ignore attempts to add beyond the ends

       return;

     }

     if (pos == size) { // Special case, tail has to be adjusted

       addLast(value);

       return;

     }

     // size and pos are guaranteed both non-zero

     ListNode ptr = head; // ptr is the node before the new one

     for(int i=0; i<pos-1; i++) {

       ptr = ptr.getNext();

     }

     ListNode newNode = new ListNode(value, ptr.getNext());

     ptr.setNext(newNode);

     size++;

  }

   

  // removes the first node and returns the value of the removed node or -1 if the list is empty

  public Integer removeFirst()

  {

     Integer retVal = -1;

     if (head != null) {

       retVal = head.getValue();

       head = head.getNext();

       size--;

     }

     if (size == 0) {

       head = tail = null;

     }

     return retVal;

  }

   

  // removes the node at position pos and returns the value of the removed node or -1 if pos is not a valid position

  public Integer removeNode(int pos)

  {

     Integer retVal = -1;

     if (head == null || pos < 0 || pos >= size) {

       return retVal;

     }

     if (pos == 0) {

       return removeFirst();

     }

     ListNode ptr = head; // ptr is the node before the deleted

     for(int i=0; i<pos-1; i++) {

       ptr = ptr.getNext();

     }

     retVal = ptr.getNext().getValue();

     if (pos == size-1) { // Is it the last element?      

       tail = ptr;

       tail.setNext(null);

     } else {

       ptr.setNext(ptr.getNext().getNext());

     }

     

     size--;

     return retVal;

  }  

   

  // finds and returns the position of find, or -1 if not found

  public int findNode(Integer find)

  {

     ListNode ptr = head;

     for(int pos=0; pos<size; pos++) {

       if (ptr.getValue() == find) {

         return pos;

       }

       ptr = ptr.getNext();

     }

     return -1;

  }  

   

  // rotates the list by placing the first element at the end

  public void rotate()

  {

     addLast(removeFirst());

  }

   

  // returns the list of values in the LinkedList

  public String toString()

  {

     String output = "";

     ListNode iter = head;

     while(iter != null) {

       output += String.format("%d ", iter.getValue());

       iter = iter.getNext();

     }

     return output;

  }

         

}

Explanation:

Enjoy. Linked list are always more complex than you expect. It is a good exercise to try once, then start using libraries. Life is too short to debug linked lists!

7 0
3 years ago
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