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astra-53 [7]
3 years ago
6

I need help ASAP due rn!

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0
There are no real solutions
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Someone steals 500, your balance is -500
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You give them the 400 change, your balance is -800

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Simplify -3(4w-3) using the distributive property
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Using a portion of her savings as a down payment, Sarah bought a new car in order to commute to her new job, reducing her saving
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3 years ago
Find the probability of being dealt a full house. (Round your answer to six decimal places.)?
vesna_86 [32]

I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.

A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.

Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.

The number of ways of drawing 2 aces and 3 2s is

\dbinom42\dbinom43=24

and the number of ways of drawing 3 aces and 2 2s is the same,

\dbinom43\dbinom42=24

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.

Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

2\dbinom{13}2\dbinom42\dbinom43=3744

The total number of hands that can be drawn is

\dbinom{52}5=2,598,960

Then the probability of getting a full house is

\dfrac{2\binom{13}2\binom42\binom43}{\binom{52}5}=\dfrac6{4165}\approx\boxed{0.001441}

4 0
3 years ago
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