2 years ago

What is y=4(x+1)^2-4 in standard form

1 answer:

6 0

Answer:

Step-by-step explanation:

(a + b)² = a² + 2ab + b²

(x + 1)² = x² +2*x*1 + 1² = x² + 2x + 1

y = 4(x+1)² - 4

y = 4(x² + 2x + 1) - 4

y = 4*x² + 4*2x + 4*1 -4

y = 4x² + 8x + 4 - 4

y = 4x² + 8x

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What is y=4(x+1)^2-4 in standard form​