-3x^2 + 12x -6
a = -3
b = 12
We calculate the vertex "x" value with this formula:
(vertex "x value") = -b / (2*a)
(vertex "x value") = -12 / -6
The vertex "x" value equals the axis of symmetry value.
The axis of symmetry is at x = 2.
Source:
http://www.1728.org/quadr3.htm
Answer:
1/8 or 0.05
Step-by-step explanation:
Answer:
Since we have BC ║ DE, we know that:
AB/AD = BC/DE
12/(12 + 4) = BC/12
12/16 = BC/12
BC = (12 · 12)/16 = 9 (in)
Applying the pythagorean, we have:
AB² + BC² = AC²
12² + 9² = AC²
225 = AC²
AC = √225 = 15 (in)
Using the information about the parallel lines again, we have:
AC/CE = AB/BD
15/CE = 12/4
CE = (15 · 4)/12 = 5 (in)
So the answer is B
Answer:
-40
Step-by-step explanation:
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