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4 years ago

What number of bales of hay does Edgar feed the horses in the barn each day ?

Mathematics

1 answer:

ladessa [460]4 years ago

4 0

Multiply the amount he feeds each horse by the number of horses.

Each horse gets 3/8 of a bale and there are 4 horses.

Total bales = 3/8 x 4

A whole number can also be written as a fraction by making the denominator ( bottom number) a 1, so 4 can be written as 4/1

So now you have 3/8 * 4/1

When you multiply fractions, multiply straight across ( multiply the two top numbers together and then the two bottom numbers together)

3/8 x 4/1 = (3*4) / (8*1) = 12/8 bales.

The answer is A

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Find (fog)(2) and (f+g)(2) when f(x) =1/x and g(x) =4x+9

Dahasolnce [82]

$( f o g)(2) = \frac{1}{17}$

$(f + g)(2) = \frac{35}{2}$

Solution:

Given that:

$f(x) = \frac{1}{x}\\\\g(x) = 4x + 9$

To find: (fog)(2) and (f + g)(2)

By composite function,

( f o g)(x) = f (g(x))

Substitute g(x) = 4x + 9 in above formula,

( f o g)(x) = f(4x + 9)

To find (fog)(2) substitute x = 2 in above formula

( f o g)(2) = f(4(2) + 9)

( f o g)(2) = f(8 + 9) = f(17)

We know that $f(x) = \frac{1}{x}$

$( f o g)(2) = f(17) = \frac{1}{17}$

$( f o g)(2) = \frac{1}{17}$

To find (f + g)(2)

We know that,

(f + g)(x) = f (x) + g(x)

Therefore,

(f + g)(2) = f(2) + g(2)

Substitute x = 2 in f(x) and g(x)

$(f + g)(2) = \frac{1}{2} + (4(2) + 9)\\\\(f + g)(2) = \frac{1}{2} + 17 = \frac{1+34}{2} = \frac{35}{2}$

$(f + g)(2) = \frac{35}{2}$

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