Approximately how many times as large was the world population as the United States population in

timama [110]

Both groups are similar.

7 0

3 years ago

A game is being played with two players. There are 21 balloons and the player who pops the last balloon wins. One or two can be

34kurt

Answer:

be the second player, and always leave a multiple of 3 balloons

Step-by-step explanation:

In order to win, a player must force the other player to leave one or two balloons. To do that, the winning player must leave one more balloon than the maximum number that can be popped. That is, the winner will be the player who leaves 3 balloons,

Working backward, we find that the winner must leave a multiple of 3 after each turn. Since the starting number is a multiple of 3, the first player must lose if the second player plays optimally.

The winning strategy is ...

be the second player
always leave a multiple of 3 balloons.

4 0

3 years ago

If you solve the inequality 2x < 14, the solution set is x < 7. Graph x < 7 on a number line. Which one of the listed v

Crazy boy [7]

Answer:

its D) x = -8 is correct

All the values less than 7 are included in the number line. The graph on number line is shown in figure attached. In the options given, all values in Option A, B and C are greater than 7 so these cannot be included.

-Hops

5 0

3 years ago

Read 2 more answers

Write the equation of the graph which is the reflection of y=−|x−1|−1 about the origin

Norma-Jean [14]

Answer:

f(x) = |x + 1| + 1

Step-by-step explanation:

A reflection over the y-axis followed by a reflection over x-axis is equivalent to a reflection about origin.

f(x) = -|x-1| -1

reflection over the x-axis:

-f(x) = (-1)*(-|x-1| -1) = |x-1| +1

reflection over the y-axis of the previous function:

-f(-x) = |-x-1| +1 = |x + 1| + 1

which is the reflection of f(x) about the origin

6 0

3 years ago

Reasoning in a laboratory, the probability a bacterial colony thrives is 70%. The numbers 0 to 6 represent the outcome that a co

Maurinko [17]

Answer:

The probability that exactly half of the colonies will thrive = (1/3) = 0.3333

Step-by-step explanation:

The list of random numbers simulates the out comes of 4 colonies.

Based On the simulation in 6 trails, what is the probability that exactly half of the colonies will thrive?

The probability of an event is given mathematically as the number of elements in the event divided the total number of elements in the sample space.

Noting that the numbers 0 to 6 indicate that a colony thrives and the number 7 to 9 represent that a colony doesn't thrive.

The 6 trials are given as

4285; 3 colonies thrive, 1 doesn't.

6903; 3 colonies thrive, 1 doesn't.

3829; 2 colonies thrive, 2 don't.

7871; 1 colony thrives, 3 don't.

2868; 2 colonies thrive, 2 don't.

5137; 3 colonies thrive, 1 doesn't.

The number of trials where exactly 2 colonies thrive = 2

The total number of trials = 6

The probability that exactly half of the colonies will thrive = (2/6) = (1/3) = 0.3333

Hope this Helps!!!

3 0

2 years ago