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s2008m [1.1K]
3 years ago
15

In a study of parents' perceptions of their children's size, researchers asked parents to estimate their youngest child's height

. The researchers hypothesize that parents tend to underestimate their youngest child's size because the youngest child is the baby of the family and all other family members appear larger compared to the baby. The sample of 39 parents who were surveyed underestimated their youngest child's height by 7.5 cm on average; the standard deviation for the difference in actual heights and estimated heights was 7.2 cm, and the data were approximately normal.
Determine the TS and p-value for this study.
Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0

Answer:

Test statistic t=6.505

P-value=0

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that parents tend to underestimate their youngest child's size.

Then, the null and alternative hypothesis are:

H_0: \mu=0\\\\H_a:\mu> 0

The significance level is assumed to be 0.05.

The sample has a size n=39.

The sample mean is M=7.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7.2}{\sqrt{39}}=1.153

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{7.5-0}{1.153}=\dfrac{7.5}{1.153}=6.505

The degrees of freedom for this sample size are:

df=n-1=39-1=38

This test is a right-tailed test, with 38 degrees of freedom and t=6.505, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>6.505)=0

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that parents tend to underestimate their youngest child's size.

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shtirl [24]

Answer:

P(B and B) = 1/9

Step-by-step explanation:

There are 4+3+5 = 12 tiles in total

The probability of selecting a B would be 4/12=1/3

When you are replacing a B tile, planning to pick a B tile again, the total tile count doesn't change. Therefore, because the two events are independent, their probabilities are multiplied and so P(B and B) = P(B) * P(B) = 1/3 * 1/3 = 1/9

3 0
3 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

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Leto [7]

Answer:

There will be 9897.47€ in the account.

La cantidad será de 9897.47€.

Step-by-step explanation:

Future value with annuity:

The future value formula, for an annuity, is:

FV = \frac{P((1+r)^{n} - 1)}{r}

An annuity means that a number of payments happen during the period(an year, for example.

P is the value of the deposit, r is the interest rate, as a decimal, and n is the number of deposits.

In this question:

1000 € each year, so P = 1000

Interest rate of 6%, so r = 0.06

One application per year for 8 years, so n = 8

Total amount:

FV = \frac{1000((1+0.06)^{8} - 1)}{0.06} = 9897.47

There will be 9897.47€ in the account.

La cantidad será de 9897.47€.

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Answer:

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Step-by-step explanation:

(x + 3)(x + 4)

x^2 + 3x + 4x + 12

x^2 + 7x +12

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