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djverab [1.8K]
3 years ago
14

Look at the system of equations below Sy= -2x +3 1 4x – 3y = 11

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

(2,-1)

y= -1

x= 2

Step-by-step explanation:

y= -2x+3

4x-3y=11

substitute the value of y into an equation

4x-3(-2x+3)=11

distribute by multiplying numbers in parenthesis by -3

4x+6x-9=11

add 4x to 6x

10x-9=11

add 9 from both sides

10x=20

divide both sides by 10

x=2

substitute the value of x into an equation

y= -2•2+3

multiply -2 to 2

y= -4+3

add -4 to 3 but 4 is negative, so subtract

y= -1

-----------

(2,-1)

-----------

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Find the range of y = -3x + 7 for the domain {-8, -6, -3, -2, 2}
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The domain is the set of x-values of a function. The range is the set of y-values of a function.

You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31

2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25

3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16

4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13

5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1

The range is {31, 25, 16, 13, 1}.

-------

Answer: 
{31, 25, 16, 13, 1}
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3 years ago
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