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Law Incorporation [45]
3 years ago
13

Prove that there is a positive number x such that x^3=5

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

x^3=5\\ x=\sqrt[3]5


and \sqrt[3]5 is positive

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POSSIBLE POINTS 10
Sergio039 [100]

Answer:

Minimum: 8 Q1: 14 Median: 17.5 Q3: 30 Maximum: 32

Step-by-step explanation:

8, 9, 11, 14, 17, 23, 29,30, 32, 32

6 0
3 years ago
The table below shows the ticket rates for whale watching trips offered by Ocean Tours. Age Ticket Price Under three years free
Mamont248 [21]
If there are 40 children aged twelve and under and x of them are under three years old, 40 - x aged three twelve years old. From the 92 people that where taken by the company on whale watching trips, 52 are over twelve years old. The equation that best show the total cost, C is
                                (40 - x)(36) + (52)(48) = C
Rearranging the equation gives,
                                       x = 40 - ((C - 2496)/ 36)
4 0
4 years ago
Solve the following system of equations by elimination. What is the value of x? x = 1.5 x = -1.5 x = 8 x = -8
Andru [333]

Using the elimination method, the value of x in the system of equations is calculated as: 8.

<h3>How to Solve a System of Equations by Elimination?</h3>

To solve a system of equations given using the elimination method, do the following:

Multiply 2x - 5y = 1 by 2 and multiply -3x + 2y = -18 by 5 to get the following:

4x - 10y = 2 --> eqn. 1

-15x + 10y = -90 --> eqn. 2

Add

-11x = -88

Divide both sides by -11

x = 8

Learn more about system of equations on:

brainly.com/question/14323743

#SPJ1

8 0
2 years ago
Help... please.I don't understand TT​
pickupchik [31]

Answer:

13. The more passengers, the more Subway cars are needed; 15. There's more weight with the more packages?

Step-by-step explanation:

4 0
4 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
3 years ago
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