This is the quadratic formula.
Answer:
okayyyyy.... then
Step-by-step explanation:
Answer:
i think it is c but idk i am doing the test rn
Step-by-step explanation:
Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
If you're not sure, begin by looking for any divisor that will divide into 24a^3c and 3a without leaving a remainder. Note that 3 is such a number, and a is another.
Factoring out 3a from 24a^3*c and 3a, we get 3a{8a^2*c, 1}
So the GCF is 3a.