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snow_lady [41]
3 years ago
8

Wes and Libbie each surveyed groups of students to find whether they would prefer going to an art museum or to the zoo. Wes foun

d that % of the students he surveyed wanted to go to the zoo. Libbie found that 60% of the students she surveyed wanted to go to the zoo. When the teachers surveyed all the students, they found that 62% wanted to go to the zoo. Which of these most likely explains why Wes's data were so different than the other two surveys?
Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0

Answer:

A.

Step-by-step explanation:

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Deffense [45]
Well what I would do first is to divide 128 by 32 which I do believe gets you 4. So now you know that 1 cup of powder can make 4 servings. So you now know that each serving only requires 1/4 cup of the powder.

So now we know Jeff went over so now we have Jeff added 2/3 and he only needs 1/4. I would now make them both equivalent by multiplying the numerator and denominator of 2/3 by 4 and the same for 1/4 but instead by 4 multiply it by 3 which you would get 2/3=8/12 and 1/4=3/12. Now subtract the two to get your answer.

8/12-3/12=5/12

Answer: He went over and he needs to remove 5/12 of the cup
5 0
3 years ago
What is the answer to <br> 3/2x - 5 = y
77julia77 [94]

Answer:

x = \frac{2y + 10}{3}

y = \frac{3}{2}x -5

Step-by-step explanation:

Hope this helps!

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3 years ago
Use the chart to multiply the binomial by the trinomial,<br> (ay: 3)( *y* 416)
Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

1,248

8 0
4 years ago
Can u answer this? respond please
lianna [129]
$1.87 is the answer

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3 years ago
Would appreciate the help ! ​
aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0
3 years ago
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