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Rudik [331]
3 years ago
10

Geometry help with number 18!

Mathematics
1 answer:
lora16 [44]3 years ago
4 0
BE is parallel to CD, therefore, m∠BEC=m∠ECD, therefore mBC=mDE
BE is the diameter, so Arc BE is 180 degree
mBC+mCD+mDE=180
replace mCD with 3mBC, and replace mDE with mBC: mBC+3mBC+mBC=180
5mBC=180
mBC=180/5=36
mCD=3mBC=3*36=108
the inscirbed angle m∠ECD= the measure of arc DE=36
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zhannawk [14.2K]

Answer:

hello your question is incomplete attached below is the complete question

answer :

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

Step-by-step explanation:

The similar integrands and the prediction ( conclusion )

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

attached below is a detailed solution

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3 years ago
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g(x)=f(5x)

this means plugging in 5x for x in f(x):

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which can be further simplified:

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Since the coefficient of x being larger means a vertical stretch, the answer is D

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