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Strike441 [17]
3 years ago
13

If you are facing east and you turn 90 degrees to your right in what direction are you now facing

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:north

Step-by-step explanation:

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What is the area of the base in the figure below? A cylinder with height 12 and diameter 6.
Naya [18.7K]

Answer:

About 28.27.

Step-by-step explanation:

To figure out the area of the base, you just use the formula to find the area of a circle. Which is;

A = r^2 * pi

(r stands for radius)

3 0
3 years ago
5(t - 3) -2t = -30 what is the answer?
maxonik [38]

Answer:

t = -5

Step-by-step explanation:

Solve for t:

5 (t - 3) - 2 t = -30

Hint: | Distribute 5 over t - 3.

5 (t - 3) = 5 t - 15:

5 t - 15 - 2 t = -30

Hint: | Group like terms in 5 t - 2 t - 15.

Grouping like terms, 5 t - 2 t - 15 = (5 t - 2 t) - 15:

(5 t - 2 t) - 15 = -30

Hint: | Combine like terms in 5 t - 2 t.

5 t - 2 t = 3 t:

3 t - 15 = -30

Hint: | Isolate terms with t to the left hand side.

Add 15 to both sides:

3 t + (15 - 15) = 15 - 30

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

3 t = 15 - 30

Hint: | Evaluate 15 - 30.

15 - 30 = -15:

3 t = -15

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 3 t = -15 by 3:

(3 t)/3 = (-15)/3

Hint: | Any nonzero number divided by itself is one.

3/3 = 1:

t = (-15)/3

Hint: | Reduce (-15)/3 to lowest terms. Start by finding the GCD of -15 and 3.

The gcd of -15 and 3 is 3, so (-15)/3 = (3 (-5))/(3×1) = 3/3×-5 = -5:

Answer: t = -5

5 0
3 years ago
Read 2 more answers
Order the numbers from least to greatest: -6, 5, -5, 6, 0
Arturiano [62]
-6,-5,0,5,6 that is the order from least to greatest
3 0
3 years ago
Need help it's difficult for me
s2008m [1.1K]

Answer:

I think 2. is A i dont know the other two

Step-by-step explanation:


8 0
3 years ago
99 POINT QUESTION, PLUS BRAINLIEST!!!
Elden [556K]
We draw region ABC. Lines that connect y = 0 and y = x³ are vertical so:
(i) prependicular to the axis x - disc method;
(ii) parallel to the axis y - shell method;
(iii) parallel to the line x = 18 - shell method.

Limits of integration for x are easy x₁ = 0 and x₂ = 9.
Now, we have all information, so we could calculate volume.

(i)

V=\pi\cdot\int\limits_a^bf^2(x)\, dx\qquad\implies \qquad a=0\qquad b=9\qquad f(x)=x^3


V=\pi\cdot\int\limits_0^9(x^3)^2\, dx=\pi\cdot\int\limits_0^9x^6\, dx=\pi\cdot\left[\dfrac{x^7}{7}\right]_0^9=\pi\cdot\left(\dfrac{9^7}{7}-\dfrac{0^7}{7}\right)=\dfrac{9^7}{7}\pi=\\\\\\=\boxed{\dfrac{4782969}{7}\pi}

Answer B. or D.

(ii)

V=2\pi\cdot\int\limits_a^bx\cdot f(x)\, dx


V=2\pi\cdot\int\limits_0^{9}(x\cdot x^3)\, dx=2\pi\cdot\int\limits_0^{9}x^4\, dx=
2\pi\cdot\left[\dfrac{x^5}{5}\right]_0^9=2\pi\cdot\left(\dfrac{9^5}{5}-\dfrac{0^5}{5}\right)=\\\\\\=2\pi\cdot\dfrac{9^5}{5}=\boxed{\dfrac{118098}{5}\pi}

So we know that the correct answer is D.

(iii)
Line x = h

V=2\pi\cdot\int\limits_a^b(h-x)\cdot f(x)\, dx\qquad\implies\qquad h=18


V=2\pi\cdot\int\limits_0^9\big((18-x)\cdot x^3\big)\, dx=2\pi\cdot\int\limits_0^9(18x^3-x^4)\, dx=\\\\\\=2\pi\cdot\left(\int\limits_0^918x^3\, dx-\int\limits_0^9x^4\, dx\right)=2\pi\cdot\left(18\int\limits_0^9x^3\, dx-\int\limits_0^9x^4\, dx\right)=\\\\\\=2\pi\cdot\left(18\left[\dfrac{x^4}{4}\right]_0^9-\left[\dfrac{x^5}{5}\right]_0^9\right)=2\pi\cdot\Biggl(18\biggl(\dfrac{9^4}{4}-\dfrac{0^4}{4}\biggr)-\biggl(\dfrac{9^5}{5}-\dfrac{0^5}{5}\biggr)\Biggr)=\\\\\\

=2\pi\cdot\left(18\cdot\dfrac{9^4}{4}-\dfrac{9^5}{5}\right)=2\pi\cdot\dfrac{177147}{10}=\boxed{\dfrac{177147\pi}{5}}

Answer D. just as before.

6 0
3 years ago
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