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4 years ago

200 is 398 times j make an equation

Mathematics

1 answer:

Snezhnost [94]4 years ago

8 0

200=398j

The 398 times j would just be 398j

is usually means equals

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The length of a rectangle is 2 inches more than twice its width, and its perimeter is 60 inches. Find the length and width of th

elena-14-01-66 [18.8K]

Answer:

2 + 2w

w = 9.3in

l = 20.7 in

Step-by-step explanation:

Perimeter of a rectangle = 2 x (length + breadth)

legnth = 2 + 2w

width = w

2 x (2 + 2w + w ) = 60

(2 + 2w + w ) = 30

2 + 3w = 30

3w = 28

w = 9.3

length = 2 + 2x9.3 = 20.7

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3 years ago

3) Solve the system of equations using elimination -9y + 4x - 2 = 0 12x - 5y + 38 = 0

timofeeve [1]

The answer is X= -4 Y=-2

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3 years ago

Which type of table shows the probability of an event occurring?

kirza4 [7]

Answer:

A. frequency table

Step-by-step explanation:

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2 years ago

Find the midpoint of a line segment that has the endpoints (3,5) and (5,-3) *

igor_vitrenko [27]

Answer:

<h3>The answer is (4 , 1)</h3>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3,5) and (5,-3)

We have

$M = ( \frac{3 + 5}{2} , \frac{5 - 3}{2} ) \\ = ( \frac{8}{2} , \frac{2}{2} )$

We have the final answer as

Hope this helps you

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3 years ago

Nagrom the Dwarf Queen desires a tunnel through the mountain to connect her two wealthiest cities, Yram and Haras, which lie on

ladessa [460]

This question requires us to use the cosine rule:

a^2 = b^2 + c^2 - 2bc*cos(A),

where A is the included angle between sides b and c, and a is the side of the triangle opposite to the angle.

In the context of the question, a is the length of the tunnel (let's call this t), b is 6 km, c is 7 km and A is 29°.

Given the values in the question and those we defined, we can rewrite the equation for the cosine rule as:

t^2 = 6^2 + 7^2 - 2(6)(7)cos(29)

Now, evaluating this we get:

t^2 = 36 + 49 - 84cos(29)

t^2 = 85 - 84cos(29)

t = sq.root (85 - 84cos(29))

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4 years ago

Read 2 more answers