The coordinate of the vertex is; (h, k) = (3, -5)
The final equation of the parabola is; y = 5(x - 3)² - 5
<h3>How to find the vertex of a Parabola?</h3>
The vertex is the coordinate of the crest or trough of the curve. Now, in the given graph, we only have a Trough which is the lowest point of the graph.
The coordinate of the vertex is; (h, k) = (3, -5)
2) Since the general equation is;
y = a(x - h)² + k
We will have;
y = a(x - 3)² - 5
At x = 2, y = 0. Thus;
0 = a(2 - 3)² - 5
a - 5 = 0
a = 5
3) The final equation of the parabola is;
y = 5(x - 3)² - 5
Read more about Parabola Vertex at; brainly.com/question/17987697
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Answer:
when x = 3, x would equal 3 since x can be substituted as 3, aka chancge any xes into 3 if they give you yhat info
Step-by-step explanation:
Step-by-step explanation:
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The slope of this line is the difference of the y values divided by the difference of the x values. Solving this give 4/-3. Then, you already know the b in y = mx+b, which is 2, because you already have the value (0, 2). So, the answer is y = x + 2
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span>
<span>(x−4<span>)2</span>−31=0</span>
<span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>