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wel
3 years ago
10

How many solutions are there to the equation below?

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

<u>c</u><u>.</u><u> </u><u>one</u><u> </u><u>solution</u>

Step-by-step explanation:

145 = 10x - 8x \\ 2x = 145 \\ x = 72.5

mario62 [17]3 years ago
3 0

Answer:

C

Step-by-step explanation:

yes

this is the answer for sure

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Write as a decimal EXACAT, NO ROUNDING<br> 1/3<br> GMM
pentagon [3]

Answer:

1/3 is equal to 0.3 repeating or 0.33333333333 to be exact

Step-by-step explanation:

I really hope this help your question wasn't very clear.

7 0
3 years ago
In one baseball season, peter hit twice the difference of the number of home runs Alice hit and 6. Altogether, they hit 18 home
Natasha2012 [34]
Peter hits 2 times the difference of the number of home runs. So Alice hits 6 home runs.
Altogether they hit 18 home runs.
2*p(18 -6)
so to figure how many home runs there r figure out the equation above.
Alice - 6
Peter - ?
(sorry if it don't help much but that what I can figure out)
3 0
4 years ago
Write the equation of a direct variation that passes through the point (-11, 13)
VMariaS [17]
<h2>Answer:</h2>

<u>A direct variation equation is of the form y = m⋅x for some constant value m</u>.

<u>For a direct variation equation passing through</u>

(x,y) = (-11,13)

13 = m × - 11

→ m = - 13/11.

so, as y = m⋅x

y = - 13/11x

<u>Hence, the direct variation equation is [C] - 13/11x</u>.

4 0
3 years ago
If z is inversely proportional to r, and z= 32 when r=1.5, find r when z=8.
lions [1.4K]
Inversely proportional: z = k/r
k = 32 * 1.5 = 48
Plug that into equation
8 = 48/r
Multiply both sides by r
8r = 48
Divide by 8
r = 6
8 0
3 years ago
(2a^x + b^x)^2 i need help ASAP
Finger [1]

Answer:

4a^{2x} + 4a^{x}b^{x} + b^{2x}

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

Given

(2a^{x} + b^{x} ) = (2a^{x} + b^{x} )(2a^{x} + b^{x} )

Each term in the second factor is multiplied by each term in the first factor, that is

2a^{x} (2a^{x} + b^{x} ) + b^{x} (2a^{x} + b^{x} ) ← distribute both parenthesis

= 4a^{2x} +2 a^{x}b^{x} + 2a^{x}b^{x} + b^{2x} ← collect like terms

= 4a^{2x} + 4a^{x}b^{x} + b^{2x}

6 0
3 years ago
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