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inna [77]
3 years ago
13

Cos ²a/2 = (tana + sina/ 2 tan a)​

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Step-by-step explanation:

<h2>Hope it helps ....</h2><h2>Moderator are worst of this app</h2>

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Find the equation of the line which passes through the point (7,2) and is perpendicular to y=5x-2
MariettaO [177]

Answer:

\displaystyle y=-\frac{1}{5}x+\frac{17}{5}

Step-by-step explanation:

<u>Equation of a line</u>

A line can be represented by an equation of the form

y=mx+b

Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

We need to find the equation of the line passing through the point (7,2) and is perpendicular to the line y=5x-2.

Two lines with slopes m1 and m2 are perpendicular if:

m_1.m_2=-1

The given line has a slope m1=5, thus the slope of our required line is:

\displaystyle m_2=-\frac{1}{m_1}=-\frac{1}{5}

The equation of the line now can be expressed as:

\displaystyle y=-\frac{1}{5}x+b

We need to find the value of b, which can be done by using the point (7,2):

\displaystyle 2=-\frac{1}{5}*7+b

Operating:

\displaystyle 2=-\frac{7}{5}+b

Multiplying by 5:

10=-7+5b

Operating:

10+7=5b

Solving for b:

\displaystyle b=\frac{17}{5}

The equation of the line is:

\boxed{\displaystyle y=-\frac{1}{5}x+\frac{17}{5}}

7 0
3 years ago
Please help me out!!!!!
amid [387]

Answer:

Step-by-step explanation:

6 0
3 years ago
If A=6x^3-x^2+4x+8 and B= 2x^3+x-5 then A-B equals
Zarrin [17]
That would be c 4x^3-x^2+3x+13
4 0
3 years ago
Can someone help me with this math homework please!
azamat

It is not necessary that the function decreasing over a given interval always be negative.

A function f(x) (value) decreases as x increases.

This does not mean that value of f(x) is negative.

It can have positive number as range.

7 0
3 years ago
Read 2 more answers
I put a picture
Ksivusya [100]

Answer:

Yes, an arrow can be drawn from 10.3 so the relation is a function.

Step-by-step explanation:

Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.

The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.

In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.

However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.

3 0
3 years ago
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