It would be -8d + 3w because
-(8d -3w)
you would be multiplying the hole equation by -1
so 8d would become -8d
and -3w would become positive +3w meaning the answer is -8d +3w
The correct answer is the graph in the top right corner because it is a constant function. The bottom left graph is also considered a function but is an absolute function. So both are technically correct.
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
=no of children who like oatmeal/toatal population*100%
=15/50*100%
=(1500/50)%
=30%
Step-by-step explanation:
One way is by using the same number
