I believe the answer should be A {(1, 6.0),(2, 5.75),(3, 5.50)}
Step-by-step explanation:
15t + 30 = 20t | -15t
30 = 5t
t = 30/5 = 6
20 + 5t = -6t + 86 | + 6t
20 + 11t = 86 | -20
11t = 66
t = 6
18t + 20 = 24t + 50 | -18t
20 = 6t + 50 | -50
-30 = 6t
t = -30/6 = -5
18t - 2 = 10t + 54 | -10t
8t - 2 = 54 | +2
8t = 56
t = 56/8 = 7
7t - 5 = 15t + 91 | -7t
-5 = 8t + 91 | -91
-96 = 8t
t = -96/8 = -12
Answer:
The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
The degree of given polynomial is '5'
the co-efficient of y⁴ is '-17'
Step-by-step explanation:
Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵
<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>
<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>
now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵
The standard form is
8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
<u><em>Conclusion</em></u>:-
<em>The degree of given polynomial is '5'</em>
<em>The co-efficient of y⁴ is '-17'</em>
<em> </em>
Answer:
(1, 1)
Step-by-step explanation: