Answer:
A. 40x + 10y + 10z = $160
B. 8 Roses, 2 lilies and 2 irises
C.
1. 20x + 5y + 5z = $80
2. 4x + y + z = $16
3. 8x + 2y + 2z = $32
Step-by-step explanation:
Cost for each flower = $160/5 = $32
So we have $32 for each bouquet consisting of 12 flowers each.
Roses = x = $2.50 each
lilies = y = $4 each
irises = z = $2 each
8x + 2y + 2z = $32
8($2.50) + 2($4) + 2($2) = $32
$20 + $8 + $4 = $32
$32 = $32
a. Maximum budget is $160
40x + 10y + 10z = $160
40($2.50) + 10($4) + 10($2) = $160
$100 + $40 + $20 = $160
$160 = $160
b. From above
8x + 2y + 2z = $32
8 Roses, 2 lilies and 2 irises
c. No. There are other solutions If total cost is not limited
1. 20x + 5y + 5z
20($2.50) + 5($4) + 5($2)
$50 + $20 + $10
= $80
2. 4x + y + z
4($2.50) + $4 + $2
$10 + $4 + $2
= $16
3. 8x + 2y + 2z
8($2.50) + 2($4) + 2($2)
$20 + $8 + $4
= $32
Answer:
4( b+3) + 2 (b + 5)
4b+12+2b+10
6b+22
Step-by-step explanation:
Answer:
859
Step-by-step explanation:
The demand for Coke products varies inversely as the price of Cole products.
Mathematically:
D α 1/p
Where D = demand, p = price of coke product
D = k/p
Where k = constant of proportionality.
Let us find k.
k = D * p
When Demand, D, is 1250, price, p, is $2.75:
=> k = 1250 * 2.75
k = $3437.5
Now, when price, p, is $4, the demand will be:
D = 3437.5/4
D = 859.375 = 859 (rounding to whole number)
The demand for the product is 859 when the price is $4.
