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3 years ago

How do you write 77/20 in a decimal

Mathematics

2 answers:

Sveta_85 [38]3 years ago

7 0

Writing it as a decimal would be 3.85 you just divide it

NISA [10]3 years ago

4 0

3.850000 i hoped i helped :)

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Solve for x in 2/3=x/4+x/3

shusha [124]

x = 8/7

hope this helps on whatever you are doing!

8 0

2 years ago

Read 2 more answers

How do you add vectors? Add the vector <3,4> to the vector that goes 7 units at an angle of 2π/3.

lawyer [7]

Answer:

The sum of the two vectors is the vector <-0.5 , 4+3.5 $\sqrt{3}$ >

Step-by-step explanation:

The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф

The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф

The vector is <b cos Ф , b sin Ф>

∵ The vector goes 7 units at an angle $\frac{2\pi }{3}$

- That means its magnitude is 7 and its direction is $\frac{2\pi }{3}$

∴ x = 7 cos( $\frac{2\pi }{3}$ )

∴ y = 7 sin( $\frac{2\pi }{3}$ )

∵ cos( $\frac{2\pi }{3}$ ) = $-\frac{1}{2}$

∵ sin( $\frac{2\pi }{3}$ ) = $\frac{\sqrt{3}}{2}$

- Substitute them in x and y

∴ x = (7)( $-\frac{1}{2}$ )

∴ x = -3.5

∴ y = (7)( $\frac{\sqrt{3}}{2}$ )

∴ y = 3.5 $\sqrt{3}$

∴ The vector is <-3.5 , 3.5 $\sqrt{3}$ >

Now lets add the vectors by adding xs and ys components

∵ <3 , 4> + <-3.5 , 3.5 $\sqrt{3}$ > = <3 + -3.5 , 4 + 3.5 $\sqrt{3}$ >

∴ <3 , 4> + <-3.5 , 3.5 $\sqrt{3}$ > = <-0.5 , 4+3.5 $\sqrt{3}$ >

∴ The sum of the two vectors is the vector <-0.5 , 4+3.5 $\sqrt{3}$ >

5 0

3 years ago

The rectangular prism has a volume of 936 cubic inches. Write and solve an equation to find the missing dimension of the prism.

nikdorinn [45]

Step-by-step explanation:

A rectangular prism is nothing but a cuboid. Let the length , width and height of the rectangular prism be l, w and h.

We know that volume of a cuboid V = l×w×h

So, l×w×h = 936

So, we can find any dimension of the prism provided the the other two dimensions are given to us.

4 0

3 years ago

An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est

nirvana33 [79]

Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.1 = 0.99$ , so $z = 1.28$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2$

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

3 0

3 years ago

Pigeon Hole Principle :

yaroslaw [1]

Answer:

A proof can be as follows:

Step-by-step explanation:

Let $S=\{a_{1},a_{2},...,a_{n},a_{n+1}\}$ be a set of $n+1$ integers. By the division algorithm the possible remainders when we divide by $n$ are $0,1,2,....,n-1$ . Then, each integer $a_{i}\in S$ can be written as:

$a_{i}=np_{i}+r_{i},\,\,0\leq r_{i}$

Observe that the set of remainders $\{r_{1},r_{2},...,r_{n+1}\}$ has $n+1$ elements and each element has $n$ possible values. By the Pigenhole principle at least two remainders have the same value. Suppose that this two elements are $a_{i}, a_{j}$ . Then,

$\begin{array}{c}a_{i}=np_{i}+r\\a_{j}=np_{j}+r\end{array}$

Where $r_{i}=r_{j}=r$ . Then, $a_{i}-a_{j}=np_{i}-np_{i}=n(p_{i}-p_{j})$ . Then we have that $n$ divides $a_{i}-a_{j}$ .

5 0

3 years ago