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3 years ago

13

A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 12 inches. If the lizard is 8 inches from a

point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.

1 answer:

Ivan3 years ago

4 0

The lizard is 2 inches away from the cactus

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If the sum of two numbers is 15 and their product is 50 what are they

Westkost [7]

Xy = 50
x + y = 15

x = 15 - y

xy = 50

(5 - y)y = 50

5y - y^2 = 50

y^2 - 5y + 50 = 0

(y - 5)(y - 10) = 0

y - 5 = 0 or y - 10 = 0

y = 5 or y = 10

x + y = 15

For y = 5:

x + 5 = 15

x = 10

For y = 10

x + 10 = 15

x = 5

Answer: the numbers are 5 and 10.

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3 years ago

Please help!!!!!!! How many inches would a point on the outer edge of the large gear travel in a 150º rotation? (The gear has a

damaskus [11]

In a full rotation, 360°, a point on the edge of a gear would travel a distance equal to its circumference. The circumference of a circle is:

C=2πr, and since we are only traveling 150°, we need to set up an appropriate ratio for circumference to the distance the point travels:

d/C=150/360

d=5C/12 and since C=2πr

d=10πr/12

d=5πr/12, and since r=4in

d=5*4π/12 in

d=20π/12 in

d=5π/3 in

d≈5.24 in (to nearest hundredth of an inch)

4 0

3 years ago

If a triangle has the same base and height will it have the same area

emmasim [6.3K]

Answer:

Yes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the sum of 4.9 × 102 and 6.8 × 103?

dusya [7]

Answer:

The sum is

$7.92\times 10^3$

Step-by-step explanation:

We want to add

$4.9\times 10^2 and 6.8\times 10^3$

The sum of these two numbers is:

$4.9\times 10^2 +6.8\times 10^3$

This is the same as:

$4.9\times 100 +6.8\times 1000$

$490 +6800=7290$

We rewrite 7290 in standard form to get;

$7.92\times 10^3$

6 0

3 years ago

The population mean annual salary for environmental compliance specialists is about $62,000. A random sample of 32 specialists

lakkis [162]

Answer: 0.002718

Step-by-step explanation:

Given : The population mean annual salary for environmental compliance specialists is about $62,000.

i.e. $\mu=62000$

Sample size : n= 32

$\sigma=6200$

Let x be the random variable that represents the annual salary for environmental compliance specialists.

Using formula $z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$ , the z-value corresponds to x= 59000 will be :

$z=\dfrac{59000-62000}{\dfrac{6200}{\sqrt{32}}}\approx\dfrac{-3000}{\dfrac{6200}{5.6568}}=-2.73716129032\approx-2.78$

Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than $59,000 :-

$P(z$

Hence, the probability that the mean salary of the sample is less than $59,000= 0.002718

3 0

3 years ago