A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 12 inches. If the lizard is 8 inches from a
point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.
1 answer:
The lizard is 2 inches away from the cactus
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Answer:
b=20
C=160
Step-by-step explanation:
160+b= 180 (sum of angle on the straight line)
b=180-160
b=20
b+c =180 (sum of angle on the straight line)
20+c=180
c=180-20
C=160
If there are 2 genders it's 2^12, which is 4096
I think it is 0.4/0.4 but I'm not sure
Answer: 2f
Explanation:
f(1)=8
f(2)= 2(8) = 16
f(3) = 2(16) = 32
f(4) = 2(32) = 64
f(5) = 2(64) =128
Answer:
24 ft
Step-by-step explanation:
a^2 + b^2 = c^2
7^2 + b^2 = 25^2
7^2 - 25^2 = -b^2
49 - 625 = -b^2
-576 = -b^2
24 = b
