Question

Identify the value(s) that are not restrictions on the variable for the rational expression

Answer 1

Answer:

5

Step-by-step explanation:

The given rational function is

$\frac{2 {y}^{2} + 2}{ {y}^{3} - 5 {y}^{2} + y - 5}$

This function is not defined when the denominator is zero.

To find the restrictions, we equate the denominator to zero and solve for y.

${y}^{3} - 5 {y}^{2} + y - 5 = 0$

We factor to get;

${y}^{2} (y - 5) + 1(y - 5) = 0$

Factor further:

$( {y}^{2} + 1) (y - 5) = 0$

${y}^{2} = - 1 \: or \: y = 5$

The real solution is

$y = 5$

The restriction is

$y = 5$

Answer 2

Answer:

The answers to this can be -1, 0, -5, and 1 the only wrong choice is five

Step-by-step explanation: