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SSSSS [86.1K]
3 years ago
9

Solve: a X (b + c); a = -3/2 , b = -2 , c = 11/3 .

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

-2  1/2

Step-by-step explanation:

a * (b + c);

Let  a = -3/2 , b = -2 , c = 11/3 .

-3/2 ( -2 + 11/3)

Get a common denominator

-3/2( -2 *3/3 + 11/3)

-3/2 ( -6/3 +11/3)

-3/2 ( 5/3)

-15/6

-5/2

Changing to a mixed number

-2  1/2

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3 years ago
(K3+2k2-82k-28)/(k+10)
Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>

  • -10 | 1 + 2 - 82 - 28
  • ---------------------------

Now firstly, drop the 1:

  • -10 | 1 + 2 - 82 - 28
  •       ↓
  • -------------------------
  •        1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

  • -10 | 1 + 2 - 82 - 28
  •       ↓ - 10
  • -------------------------
  •        1 - 8

Next, multiply -10 and -8, then combine the product with -82:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80
  • -------------------------
  •        1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80 + 20
  • -------------------------
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Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

<u>Putting it together, the quotient is k^2-8k-2-\frac{8}{k+10}</u>

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Answer: 11. Is A

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

This expression can be rewritten as

8

----

9

======

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 ---

  9

If we now invert the denominator fraction 4/9 and multiply the result, we get:

 8       9

----- * ----- = 2

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