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svetlana [45]
3 years ago
10

In Ryan Corporation, the first shift produced 5 1/2 times as many light bulbs as the second shift. If the total light bulbs prod

uced were 16,250, how many light bulbs were produced on shift 1?
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

Step-by-step explanation:

It appears that the number of bulbs produced on the first shift is quite a bit more than the second shift.  5.5 times more, actually.  That means that the first shift's output is based on the second shift's output.  Second shift produced an unknown number of bulbs, so we will call that number x.  First shift produced 5.5 times more, so first shift produced 5.5x.  The total number of bulbs produced between the 2 shifts is given as 16,250, so

x + 5.5x = 16,250 so

6.5x = 16,250 and

x = 2500

The second shift produced 2500 bulbs, and the first shift produced 5.5(2500) = 13,750 bulbs.

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schepotkina [342]

Answer:


Step-by-step explanation:

Given problems are absolute value problems, So we need to plug the values of given parameters and get the final result.

We have given here,

a =-2 , b = 3 ,  c = -4 and d = -6

Now we know that An absolute function always gives a positive value.

Let's apply this strategy in the given problems.

1. ║a+b║

Plug a= -2 and b = 3

We get, ║-2+3║=║1║= 1

2. 5║c+b║

Plug c= -4 and b=3

i.e.   5║-4 + 3║= 5║-1║=5×1 = 5

3. a+b║c║

Plug values a= -2 , b=3 and c=-4

i.e -2 +3║-4║ = -2 + 3×4 = -2 + 12 = 10

4. ║a+c║÷(-d)

i.e ║-2 + (-4)║÷(-6) = ║-6║÷(-6) = 6÷(-6) = -1

5. 3║a+d║+b

i.e 3║-2+(-6)║+3 = 3║-8║+3 = 3×8 +3 = 27

4 0
3 years ago
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Answer:

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Step-by-step explanation:

The happiest would be

Null hypothesis: u <= 80

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