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ahrayia [7]
3 years ago
10

Someone please help!! I’ll give you Brainliest!

Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

x= 1

y= 2

(1,2)

x=2

y=3

(2,3)

x=3

y=4

(3,4)

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Suppose X and Y have joint density f(x,y)=1 for 0
SashulF [63]

∫¹₀ min (1, n/y)dy = ∫ⁿ₀ (1, n/y)dn + ∫¹n min (1, n/y) dy

Hope this helps


8 0
3 years ago
Which of the following is NOT a variation of a Pythagorean identity?​
Ipatiy [6.2K]

The expression that is not a variation of the Pythagorean identity is the third option.

<h3>What is the Pythagorean identity?</h3>

The Pythagorean identity can be written as:

sin^2(x) + cos^2(x) = 1

For example, if we subtract cos^2(x) on both sides we get the second option:

sin^2(x) = 1 - cos^2(x)

Which is a variation.

Now, let's divide both sides by cos^2(x).

sin^2(x)/cos^2(x) + cos^2(x)/cos^2(x) = 1/cos^2(x)\\\\tan^2(x) + 1 = sec^2(x)\\\\tan^2(x) - sec^2(x) = -1

Notice that the third expression in the options looks like this one, but the one on the right side is positive. The above expression is in did a variation of the Pythagorean identity, then the one written in the options (with the 1 instead of the -1) is incorrect, meaning that it is not a variation of the Pythagorean identity.

Concluding, the correct option is the third one.

If you want to learn more about the Pythagorean identity, you can read:

brainly.com/question/24287773

3 0
3 years ago
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
a student says that if 5x^2 = 20, then x must be equal to 2. do u agre or disagree with the student? justify your answer.​
inna [77]

Answer:

The student is correct.

Step-by-step explanation:

Given that 5x² = 20:

It is true that the value of x = 2 because 2² = 4, and when you multiply 4 with 5, you'll get a product of 20:

5x² = 20

5(2)² = 20

5(4) = 20

20 = 20

Therefore, the student is correct that x = 2.

7 0
2 years ago
Will Mark Brainliest
GaryK [48]

The correct answer is D

5 0
3 years ago
Read 2 more answers
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