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3 years ago

10

Someone please help!! I’ll give you Brainliest!

1 answer:

Valentin [98]3 years ago

5 0

Answer:

x= 1

y= 2

(1,2)

x=2

y=3

(2,3)

x=3

y=4

(3,4)

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Please help with this question

Eddi Din [679]

Answer:

92°

Step-by-step explanation:

We can say that the angle that is of x degrees is an inscribed angle because its vertex is on the circle and its sides are made up of rays. When you have an inscribes angle, it measures exactly half the angle it intercepts. In this case that angle is 184°. So, because of this we can say:

x = 184° / 2

x = 92°

6 0

3 years ago

Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1

geniusboy [140]

Answer:

Step-by-step explanation:

eq. of directrix is y-1=0

let (x,y) be any point the parabola.

then\sqrt{ (x-6)^2+(y-2)^2}=\frac{y-1}{(-1)*2}

squaring

x²-12x+36+y²-4y+4=y²-2y+1

x²-12 x+40-1=4y-2y

2y=x²-12x+39=x²-12x+36+3

(x-6)²=2y-3

5 0

3 years ago

A roofer calculates his bid price using the formula P = 1.85s + 4.2f, where s is the area of the roof in square feet and f is th

solmaris [256]

Answer: 1,811 square foot

Step-by-step explanation:

Hi, to answer this question we have to solve the equation given, by substituting P = 4,148 and f=190 in the equation.

P = 1.85s + 4.2f

4,148 = 1.85s +4.2 (190)

Solving for s:

4,148 = 1.85s +798

4,148-798 =1.85s

3,350 = 1.85s

3,350/1.85 =s

s = 1,810.81 = 1,811 square foot (rounded)

Feel free to ask for more if needed or if you did not understand something.

8 0

3 years ago

Read 2 more answers

GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out

Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

$Area=length\times width$

Area of garden and the walkway together is

$Area=(14+2x)\times (10+2x)$

$396=140+28x+20x+4x^2$

$396=140+48x+4x^2$

$396=4(35+12x+x^2)$

Divide both sides by 4.

$99=35+12x+x^2$

$0=35-99+12x+x^2$

$0=-64+12x+x^2$

Splitting the middle term, we get

$x^2+16x-4x-64=0$

$x(x+16)-4(x+16)=0$

$(x+16)(x-4)=0$

Using zero product property, we get

$(x+16)=0\text{ and }(x-4)=0$

$x=-16\text{ and }x=4$

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

6 0

3 years ago

Read 2 more answers

How do you write the equation of the horizontal line passing through (1,9)?

Leviafan [203]

he equation of any horizontal line is

y = .. a number

The x-value has no effect on the equation or on the line at all, as long as y-value stays the same.

In this case the line passes though the point (−8,9)

which tells us that the y-value we want is 9.

Therefore the equation is y=9

4 0

3 years ago