Answer:
<em>I think the best answer will be is</em><em> C. 1.3 Good Luck!</em>
Answer:520; 240
Step-by-step explanation:
a. 13, 26, 39, 52,......
a = First term = 13
d = common difference = 26 - 13 = 13
40th term = a + (n - 1)d = a + (40-1)d = a + 39d
= 13 + (39 × 13)
= 13 + 507
= 520
b. 6, 12, 18, 24,.......
a = First term = 6
d = common difference = 12 - 6 = 6
40th term = a + 39d
= 6 + 39(6)
= 6 + 234.
= 240
Answer:
Addition of 323+412 = 1240 at base 5
Step-by-step explanation:
We have to add 323+412 on base 5
As we have to use base 5 for addition so we can use only numbers 0,1,2,3.4 and 5 as we use 0,1,2,3,4,5,6,7,8,9,10 in decimal when base is 10
Means in addition of sum is greater than 5 then we have to take carry as in base 10 we take carry if the sum is greater than 10
So sum 323+412 = 1240
Answer:
84.3%
Step-by-step explanation:
You first find the frequency. You do this by multiplying the frequency density by the class length.
