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saveliy_v [14]
3 years ago
12

HoConjecture #1- The sum or difference of two rational numbers is always?

Mathematics
1 answer:
charle [14.2K]3 years ago
5 0

the sum or difference of two rational numbers is always RATIONAL

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Find the quotient 12÷3/8
bearhunter [10]

Answer:

32

Step-by-step explanation:

To make it a fraction form answer, you multiply the whole number by the denominator and make the result the new numerator. The old numerator becomes the new denominator

 

Thus, the answer to 12 divided by 3/8 in fraction form is:

96 /3

To make the answer to 12 divided by 3/8 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

96 / 3 = 32

The answer is rounded to the nearest two decimal points if necessary.

96/3 can be simplified to 32/1.

32/1 is an improper fraction and should be written as 32.

Hope this helps <3

3 0
2 years ago
Read 2 more answers
Mika wants to buy a condominium. He has the choice of buying it now or renting it with the option to buy at the end of 3 years.
mixer [17]

Answer:

Step-by-step explanation:

 

$828

5 0
3 years ago
Read 2 more answers
Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
1. The Cajun Heartland State Fair charges $1.25 per ticket for the rides. Johnny bought 25 tickets for the rides and spent a tot
vladimir1956 [14]

<u>Part (a)</u>

The variable y is the dependent variable and the variable x is the independent variable.

<u>Part (b)</u>

The cost of one ticket is $1.25. Therefore, the cost of 25 tickets will be: .

Now, we know that Johnny spent his money only on ride tickets and fair admission and that he spent a total of $43.75.

Therefore, the price of the fair admission is: $43.75-$31.25=$12.5

If we use y to represent the total cost and x to represent the number of ride tickets, the linear equation that can be used to determine the cost for anyone who only pays for ride tickets and fair admission can be  written as:

y=1.25x+12.5......Equation 1

<u>Part (c)</u>

The above equation is logical because, in general, the total cost of the rides will depend upon the number of ride tickets bought and that will be 1.25x. Now, even if one does not take any rides, that is when x=0, they still will have to pay for the fair admission, and thus their total cost, y=$12.5.

Likewise, any "additional" cost will depend upon the number of ride tickets bought as already suggested. Thus, the total cost will be the sum of the total ride ticket cost and the fixed fair admission cost. Thus, the above Equation 1 is the correct representative linear equation of the question given.

7 0
2 years ago
Jack wants to purchase a Wallet for $33. He currently has $18 . By how much money will he be in debt if he decides to borrow the
Semmy [17]

Answer:

$15 in debt

Step-by-step explanation:

Subtract 33 from 18

18 - 33

= -15

So, he will be $15 in debt

4 0
2 years ago
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