F(x)=2x^2-5;find when f(x)=-7
2 answers:
Answer:
±i = x
Step-by-step explanation:
f(x)=2x^2-5;
f(x)=-7
-7 = 2x^2 -5
Add 5 to each side
-7+5 = 2x^2 -5+5
-2 =2x^2
Divide by 2
-2/2 =2x^2 /2
-1 = x^2
Take the square root of each side
sqrt(-1) = sqrt(x^2)
±i = x
Answer:
x=i or no solution exists depending on the user's grade
Step-by-step explanation:
f(x) = 2x^2-5
-7 = 2x^2-5
-2 = 2x^2, x^2=-1, x=i
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