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kirill115 [55]
3 years ago
13

A change in a sequence of DNA bases in a bacterial cell has resulted in a mutation. This mutation has increased the ability of t

he bacteria to break down and digest organic molecules in the environment. Bacteria with this mutation are better able to find and utilize food sources. According to the theory of natural selection, select the change that is MOST likely to occur in future generations of this bacteria.
Biology
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

The relative frequency of the mutation will increase as time passes.

Explanation:

This random mutation has, by chance, caused a phenotype that is beneficial to the bacteria. This mutation improves the fitness of the bacteria, as they are able to utilize more food sources. This reduces the chance of starvation and death of the cell. Therefore, cells with this mutation are more likely to survive, and for longer.

In times where nutrients are scarce, bacteria without the population will die off. But the bacteria with this mutation will be more likely to survive and pass on their genetic material. Therefore, over time, the frequency of this mutation will increase.

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choli [55]

Answer:

omg I just did these in class. the answer is like this:

the boxes are: (top left corner) Bb, (top right corner) bb, (bottom left corner) Bb, (bottom right corner) bb

1.

a. potential genotypes: Bb (50%), bb (50%)

b. potential phenotypes: pls dont take my word for this part, bc im not that good here, but I think its brown eyes (50%), blue eyes (50%)

Hope this helped!

4 0
3 years ago
Read 2 more answers
G542x is another cftr allele. If a female heterozygous for g542x bears a child fathered by a male heterozygous for the δf508 all
Amiraneli [1.4K]

Probability that the child would be homozygous for the g542x allele 0.00

<h3>why the probability is nil?
</h3>
  • The kid cannot be homozygous for the G542X gene since only the mother has it; the father, on the other hand, has a mutant dF508 allele and so cannot pass on a copy of mutant G542X = never homozygous recessive child.
  • A kid must have the G542X allele from both parents in order to be homozygous for the G542X allele. Because only the mother possesses the G542X gene, the child's chances of being homozygous for the G542X allele are 0.00
<h3>When offspring show a blend of the parents traits one allele is dominant over the other?</h3>
  • At the point when one allele is predominant over another, posterity show a mix of guardians' qualities.
  • The heterozygous aggregate in complete predominance is tracked in the middle of between two homozygous aggregates. A heterozygous individual showcases qualities of the two guardians in the event of codominance.

To learn more about hetrozygous from the given link

brainly.com/question/1626661

#SPJ4

4 0
1 year ago
What is the formula mass of sulfur dioxide
Oxana [17]

Answer:

Mr(SO2)=32+16*2=64

Explanation:

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The answer is C. composite volcanoes

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