Question

Sebuah lilin diletakkan di depan lensa cembung. Bayangan maya yang dihasilkan 1,2 kali tinggi benda. Jarak benda ke lensa 5 cm. Tentukan fokus lensa cembung !

Answer 1

Answer:

Focal length of the convex lens is 2.72 cm

Explanation:

As we know that the convex lens produce 1.2 times magnified image

Now we know that the object distance from the lens is 5 cm

so we have

$\frac{d_i}{d_o} = 1.2$

now we have

$d_i = 1.2 \times 5 = 6 cm$

now by the formula of lens

$\frac{1}{6} + \frac{1}{5} = \frac{1}{f}$

$f = 2.72 cm$